Math, asked by nitu4360, 4 months ago

if ten A=3/4, find the value of cos A​

Answers

Answered by premnathawasthi3
0

Step-by-step explanation:

tan A =3/4=PERPENDICULAR/BASE

AB=4;BC=3

then in triangle by Pythagoras theorem

(AC)^2=(AB)^2+(BC)^2

(AC)^2=(4)^2+(3)^2

(AC)^2=16+9

(AC)^2=25

AC=5=HYPOTENUSE

sin A=Perpendicular/hypotenuse

sin A=3/5

cos A=Base/hypotenuse

COS A=4/5

1/sin A=1 / 3/5

1/cos A=1 / 4/5

1/sin A+1/cos A

=1/3/5+1/ 4/5

=5/3+5/4

=20+15/12

=35/12

HOPE IT HELPS

PLEASE MAKE ME BRAINLIEST

Answered by aarohi10266
1

Answer:

I hope this will helpful to you

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