if ten A=3/4, find the value of cos A
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Step-by-step explanation:
tan A =3/4=PERPENDICULAR/BASE
AB=4;BC=3
then in triangle by Pythagoras theorem
(AC)^2=(AB)^2+(BC)^2
(AC)^2=(4)^2+(3)^2
(AC)^2=16+9
(AC)^2=25
AC=5=HYPOTENUSE
sin A=Perpendicular/hypotenuse
sin A=3/5
cos A=Base/hypotenuse
COS A=4/5
1/sin A=1 / 3/5
1/cos A=1 / 4/5
1/sin A+1/cos A
=1/3/5+1/ 4/5
=5/3+5/4
=20+15/12
=35/12
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