If ten students are asked to measure the
length of a piece of cloth up to a mm, using a
metre scale, do you think their answers will
be identical? Give reasons.
Answers
Answer:
the measured distance by the student is 3.50 cm which means the least count of the measurement done is 0.01 cm.
he measured distance by the student is 3.50 cm which means the least count of the measurement done is 0.01 cm. A screw gauge having 100 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(100) i.e. 0.01 mm
he measured distance by the student is 3.50 cm which means the least count of the measurement done is 0.01 cm. A screw gauge having 100 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(100) i.e. 0.01 mmsimilarly screw gauge having 50 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(50) i.e. 0.5 mm
he measured distance by the student is 3.50 cm which means the least count of the measurement done is 0.01 cm. A screw gauge having 100 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(100) i.e. 0.01 mmsimilarly screw gauge having 50 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(50) i.e. 0.5 mmA meter scale has a least count of 1 mm.
he measured distance by the student is 3.50 cm which means the least count of the measurement done is 0.01 cm. A screw gauge having 100 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(100) i.e. 0.01 mmsimilarly screw gauge having 50 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(50) i.e. 0.5 mmA meter scale has a least count of 1 mm.And the least count of a vernier caliper which has 10 divisions in 1 cm on main scale and 10 divisions in vernier scale match with 9 division in main scale can be given as
he measured distance by the student is 3.50 cm which means the least count of the measurement done is 0.01 cm. A screw gauge having 100 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(100) i.e. 0.01 mmsimilarly screw gauge having 50 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(50) i.e. 0.5 mmA meter scale has a least count of 1 mm.And the least count of a vernier caliper which has 10 divisions in 1 cm on main scale and 10 divisions in vernier scale match with 9 division in main scale can be given as 1 cm/(10*10) = 0.01 cm
he measured distance by the student is 3.50 cm which means the least count of the measurement done is 0.01 cm. A screw gauge having 100 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(100) i.e. 0.01 mmsimilarly screw gauge having 50 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(50) i.e. 0.5 mmA meter scale has a least count of 1 mm.And the least count of a vernier caliper which has 10 divisions in 1 cm on main scale and 10 divisions in vernier scale match with 9 division in main scale can be given as 1 cm/(10*10) = 0.01 cmThus the student must have used the vernier caliper for the measurement.
Answer:
yes
Explanation:
If they are sincere students they all will get identical answers.