Question

If tetha = 45, then find the value of 2 sin^2 tetha + 3 cose^2 tetha

Answer 1

$\bigstar \underline{\underline{\sf \bf Given:- }}$

• Value of θ = 45°.

$\bigstar \underline{\underline{\sf \bf To\ find:- }}$

• Value of 2sin²θ+3cosec²θ

$\bigstar \underline{\underline{\sf \bf Solution:- }}$

We know :

$\mapsto \boxed{ \sf Sin\ 45^o = \frac{1}{\sqrt{2} } }\\\\\\\mapsto \boxed{\sf Cosec\ 45^o = \sqrt{2} }$

According to question :

$:\implies \sf 2sin^2 \theta + 3 cosec^2 \theta \\\\\\:\implies \sf 2sin^2 45^o + 3 cosec^2 45^o\\\\\\:\implies \sf 2(\frac{1}{\sqrt{2} } )^2 + 3(\sqrt{2} )^2\\\\\\:\implies \sf 2(1/2)+3(2)\\\\\\:\implies \sf 1+6 = 7.$

$\\\\ \therefore \orange{\boxed{\sf 2sin^2 \theta +3cosec^2 \theta = 7. }}$

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Answer 2

NICE QUESTION REALLY NICE QUESTION

BUT URE HURTS ME.... XD

ABOVE ANS IS RIGHT XD