Question

if
${2}^{3} \times {9}^{2} \div {8}^{2} \times {3}^{5} = x \:the \: value \: of \: x \: is$
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Answer 1

${2}^{3} \times {9}^{2} \div {8}^{2} \times {3}^{5} = x \\ So, \\ x = \frac{ {2}^{3} \times {9}^{2} }{ {8}^{2} \times {3}^{5} } = \frac{2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 3 \times 3 } \\ \: \: \: = \frac{1}{2 \times 2 \times 2 \times 3 \times 3} = \frac{1}{8 \times 9} \: \: \\ \: \: \: = \frac{1}{72}$