Question

if ,
$( {2}^{3x - 1} + 10) \div 7 = 6$
then find x is equal to
(with Full explanation)​

Answer 1

Answer:

Given ,

{2^(3x-1) +10 } ÷7 = 6

=> { 2^(3x-1) +10 } = 42

=> { ( 2^3x ) ÷ 2 + ( 20 ÷2 )} =42

=> (2^3x +20)÷2 =42

=> (2^3x +20) = 84

=> 2^3x = 64

=> 2^3x = 2^6

=> 3x=6 { Exponents are equal when equal bases with certain exponents are equal. }

=> x=2.

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