Question

if
${2}^{5x} \div {2}^{x} = \sqrt[5]{32} .then \: find \: the \: value \: of \: x$
​

Answer 1

ANSWER:

step by step _

${2}^{5x} \div {2}^{x} = \sqrt[5]{32}$

${2}^{4x} = ({32})^{1 \div 5}$

${2}^{4x} = ( {2}^{5} )^{1 \div 5}$

${2}^{4x} = {2}^{5 \div 5} = {2}^{1}$

now on comparing powers we will get,

=> 4x = 1

=> x = 1/4___ans.

Thnks!!♥️