Math, asked by Artee5373, 1 month ago

If 2 \frac{1}{4} \div 1 \frac{1}{2} \: of \: (4 \frac{1}{6} - ( \frac{17}{21} + 1 \frac{1}{3} \times 2 \frac{1}{8} \div 1 \frac{1}{6} \: of \: \frac{3}{4} - \frac{3}{4} \times \frac{20}{21} )) = \frac{a}{b} , where HCF of a and b is 1, what is the value of (2a-3b)? ​

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Answered by kankit60298
0

Answer:

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