Question

If
$2 \sin( \alpha ) - 1 = 0$
find
$3 \tan( \alpha { }^{2} ) + 8 \cos( \alpha {}^{2} ) - 5$
​

Answer 1

$\sin( \alpha ) = \frac{1}{2} \\ \sin(30) = \frac{1}{2} \\ so \: put \: value \: of \alpha \\ { 3\ \tan( \alpha ) }^{2} + 8 { \cos( \alpha ) }^{2} - 5 \\ = 3 \times \frac{1}{ { \sqrt{3} }^{2} } + 8( \frac{ { \sqrt{3} }^{2} }{2} ) - 5 \\ = 1 + 6 - 5 \\ = 2$

I hope it will help you. Please mark brainliest answer....

Answer 2

The answer is 8. Solution in attachment.