Question

if
${2}^{x + 1 } = {3}^{1 - x}$
then find the value of x​

Answer 1

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Answer 2

Step-by-step explanation:

We have,

${2}^{x +1 } = {3}^{1 - x}$

$\implies log_{2}( {2}^{x + 1} ) = log_{2}( {3}^{1 - x} )$

$\implies(x + 1) = (1 - x) log_{2}(3)$

$\implies \: x(1 + log_{2}(3) ) = log_{2}(3) - 1$

$\implies \: x = \frac{ log_{2}(3) - 1}{ log_{2}(3) + 1 }$