Question

If
$21168 = {x}^ {4} \times {y}^{3 } \times {z}^{2}$
find the value of x, y,z.​

Answer 1

Answer is

${2}^ {4} \times {3}^{3 } \times {7}^{2}$

x = 2 , y = 3 , z = 7

Answer 2

Answer:

Prime factors of 21168=( 2 to the power 4)*( 3 to the power 3 )* (7 to the power 2)

Therefore x is 2, y is 3 and z is 7.

x + y+ z= 12

X + y =5

Y+z =10

Required answer is 24