Question

if
${27}^{x + 1} = {9}^{x + 3} = {3}^{y}$
, then find
$\frac{x}{y}$
answer it with explaination​

Answer 1

Step-by-step explanation:

${27}^{x + 1} = {9}^{x + 3} = {3}^{y}$

${3}^{3(x + 1)} + {3}^{2(x + 1)} = {3}^{y}$

${3}^{3x + 3} = {3}^{2x + 2} = {3}^{y}$

equating the bases

$3x + 3 = 2x + 2 = y$

finding the values of x and y

$3x + 3 = 2x + 2$

$x = - 1$

$y = 2x + 2$

$y = 2( - 1) + 2$

$y = - 2 + 2$

$y = 0$