Question

if
$27 {}^{x} = \frac{ {9}^{} }{3 {}^{x} }$
find x

Answer 1

${3}^{3} = \frac{ {3}^{2} }{ {3}^{x} } \\ {3}^{3} = {3}^{2 - x} \\ on \: comparing \: \\ 3 = 2 - x \\ x = - 1$

Hope it will help you

Answer 2

${\purple{hola!}}$
${\green{x=1/2}}$