Question

If
$( {3}^{2x + 1} + 9) \div 9 = 10$
Find the value of x.

Answer 1

3^2x+1/9=27
3^2x+1=27*9
3^2x+1=243
(3)^2x+1=(3).^5
3 will cancel out 
So,
2x+1=5
2x=5-1
2x=4
x=4/2
x=2