Question

If
${3}^{x - 1} = (27) \: and \: {4}^{y + 2} = 4. \: find \: the \: value \: \\ of \: \frac{y}{x} - \frac{x}{y}.$
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Answer 1

Answer:

${3}^{x - 1} = 27 \\ {3}^{x - 1} = {3}^{3} \\ \\ x - 1 = 3 \\ x = 4 \\ . \\ {4}^{y + 2 } = 4 = {4 }^{1} \\ \\ y + 2 = 1 \\ y = - 1$

$\frac{y}{x} - \frac{x}{y} = \frac{ - 1}{4} + \frac{4}{1} = \frac{15}{4} \\ \\ mark \: as \: brainlist \: ans$

Answer 2

Answer:

☆

${3}^{x - 1} = 27 \\ {3}^{x - 1} = {3}^{3} \\ x - 1 = 3 \\ x = 4$

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${4}^{y + 2} = 4 \\ {4}^{y + 2} = {4}^{1} \\ y + 2 = 1 \\ y = - 1$

☆

$\frac{y}{x} - \frac{x}{y} = \frac{ - 1}{4} - ( \frac{4}{ - 1} ) = - \frac{1}{4} + \frac{4}{1} = \frac{ - 1 + 16}{4} = \frac{15}{4}$

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