Question

if
$3 ^{x - 1} = 9$

and
$4^{y + 2} = 644$

,what is the value of
$\frac{x}{y}$

​

Answer 1

Step-by-step explanation:

3

3^x-1 = 3^2

x-1 = 2

X = 3

4^y+2 = 4^3

y+2 = 3

y = 1

X/y = 3/1 = 3

Answer 2

$\large \green{ \fcolorbox{gray}{black}{ ☑ \: \textbf{Verified \: answer}}}$

$\bf {3}^{x - 1} = 9 \\ \\ \bf \: {3}^{x - 1} = {3}^{2} \\ \\ \bf \: {x - 1} = 2 \\ \\ \bf \: x = 3$

$\bf \: {4}^{y + 2} = 64 \\ \\ \bf \: {4}^{y + 2} = {4}^{3} \\ \\ \bf \: {y + 2} = 3 \\ \\ \bf \: y = 1$

$\boxed{ \huge \pmb{ \frac{x}{y} = \frac{3}{1} = 3}}$