Question

 if $4^x+^3 = 112+8 *4^x$ then find $(18x)^3^X$

Answer 1

Let 4^x = y then the equation become ....... 4^3 y = 112 + 8y => 64y -8y = 112 => 56y =112 => y = 2 => 4 ^x = 2 => 2^2x = 2^1 => 2x = 1 => x= 1/2 now we have to find (18x) ^3x => (18*1/2)^3/2=> 9^3/2 => (9^1/2)^3 => 3^3 => 27 Answer