Math, asked by afsarunnusa, 8 hours ago

if
${8}^{x} + 1 = 1then \: x$
help in this problem

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Answered by Gauthmathspark

0

Answer:

x = -1

Step-by-step explanation:

${8}^{x + 1} = 1 \\ {8}^{x + 1} = {8}^{0} \\ x + 1 = 0 \\ x = - 1 \\$

Answered by Gauthmath

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