Math, asked by lolsolveme, 3 months ago

if
a {}^{2} + 6a + 1 = 0
a) Find the the value of
a +  \frac{1}{a}



Answers

Answered by gopalpvr
1

Answer:

-6

Step-by-step explanation:

a2+6a+1=0

a2+1=-6a

consider

a+ 1/a

= (a^2 +1)/a

= -6a/a

= -6

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