Question

If =
${a}^{2} + \frac{1}{ {a}^{2} } = 102$
find the value of
$a - \frac{1}{a} .$
please solve it don't give irreverent answer I will report his/her answer​

Answer 1

Answer:

${a}^{2} + \frac{1}{ {a}^{2} } = 102$

$ans \: ) \: a - \frac{1}{a} = 10$

Step-by-step explanation:

using the identity

$(x-y)^2 =x^2 +y^2 - 2xy$

$(a- \frac{1}{a})^2 = a^2 + (1/a)^2 - 2$

$(a- \frac{1}{a})^2 = 102 - 2$

$a - \frac{1}{a} = \sqrt{100}$

$a - \frac{1}{a} = 10$