If
, find the value of a and b
Answers
Answered by
2
Answer:
Given
\dfrac{3}{2-\sqrt{2} } = a+b\sqrt{2}
LHS
= \dfrac{3}{2-\sqrt{2} }
= \dfrac{3}{2-\sqrt{2} } \times \dfrac{2+\sqrt{2} }{2+\sqrt{2} }
= \dfrac{6+3\sqrt{2} }{(2)^{2} -(\sqrt{2})^{2} }
= \dfrac{6+3\sqrt{2} }{4-2 }
= \dfrac{6+3\sqrt{2} }{2 }
= 2 + \dfrac{3\sqrt{2} }{2}
Therefore,
\boxed{\boxed{\bold{a=2}}}}}}}}}
\boxed{\boxed{\bold{b=\frac{3}{2} }}}}}
Similar questions