Question

if
$a \frac{1}{3} + b \frac{1}{3} + c \frac{1}{3} = 0$
then

$( {a + b + c})^{3}$
prove​

Answer 1

PROOF:

${a}^{ \frac{1}{3} } + {b}^{ \frac{1}{3} } + {c}^{ \frac{1}{3} } = 0 \\ {({a}^{ \frac{1}{3} } + {b}^{ \frac{1}{3} } + {c}^{ \frac{1}{3} })}^{3} = 0 \\ (a + b + c) = 0 \: \: \: \: \: \: \: \: \: \\ {(a + b + c)}^{3} = 0$

Answer 2

Step-by-step explanation:

a

3

1

+b

3

1

+c

3

1

=0

(a

3

1

+b

3

1

+c

3

1

)

3

=0

(a+b+c)=0

(a+b+c)

3

=0