If ![A=\left[\begin{array}{ccc}3&-4\\1&-1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26amp%3B-4%5C%5C1%26amp%3B-1%5Cend%7Barray%7D%5Cright%5D "A=\left[\begin{array}{ccc}3&-4\\1&-1\end{array}\right]")
then prove that ![A^{n} =\left[\begin{array}{ccc}1+2n&-4n\\n&1-2n\end{array}\right]](https://tex.z-dn.net/?f=A%5E%7Bn%7D+%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2B2n%26amp%3B-4n%5C%5Cn%26amp%3B1-2n%5Cend%7Barray%7D%5Cright%5D "A^{n} =\left[\begin{array}{ccc}1+2n&-4n\\n&1-2n\end{array}\right]")
where n is any positive integer.
Answers
Answered by
0
Answer:
if we put
n=1.2.3.4.5... in A raise to power n
then we can get the same answer as A
Similar questions