Question

If $a_{n} = \frac{n(n-3)}{n+4}$, find the 18th term of this sequence.

Answer 1

hello ,,,,,,,

⏩⏩a{n} =n(n-3)/n+4

a{18}= 18(18-3)/18+4

== 18×15/22
== 270/22= 135/11

Answer 2

Answer:

135/11

Step-by-step explanation:

Given nth term of an the sequence is an = n(n - 3)/(n + 4).

18th term:

a₁₈ = 18(18 - 3)/(18 + 4)

    = 18 * 15/(22)

    = 270/22

    = 135/11.

Therefore, 18th term of this sequence = 135/11.

Hope it helps!