Math, asked by 1909020482321a, 11 hours ago

If
a \:  \times b =  {a}^{2}  -  {b}^{2}  +2ab \:  \: and \: a \:  \div b \:  =  {a }^{2}  \:  +  {b}^{2}  - 2ab.then \: what \: is \: the \: value \: of \: (2 \times 3) + (4 \div 5)
?
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Answers

Answered by Sarahcosta
3

Answer:

a-b+c

Step-by-step explanation:

Given equation is a2−2ab−c2+b2

We can write the given equation as,

⇒ a2−2ab+b2−c2

⇒ (a−b)2−c2              ....Since (a2−2ab+b2=(a−b)2)

Also we know,

m2−n2=(m+n)(m−n)

Here, m=(a−b) and n=c

Thus a2−2ab−c2+b2=(a−b+c)(a−b−c)

Factors are (a−b+c) and (a−b−c).

Answered by tribenisaikia01
2

Answer:

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