Math, asked by palakshukla09, 11 months ago


if
 \alpha  \: and \:  \beta  \: are \: the \: zeros \: of \: the \: qudrtc \: polynomil \: f{x} = ax {?}^{2}  + bx + c \: then \: evalute \:  \alpha  {?}^{2}  +  \beta  {?}^{2}


Answers

Answered by MarkAsBrainliest
2
Solution :

Given polynomial is

f (x) = ax² + bx + c ...(i)

Since, α and β are the roots of (i) no. polynomial, by the relation between roots and coefficients, we get

α + β = -\frac{b}{a} ...(ii)

αβ = \frac{c}{a} ...(iii)

Now, α² + β²

= (α + β)² - 2αβ

= (-\frac{b}{a})^{2} - 2 (\frac{c}{a})

= \frac{b^{2}}{a^{2}}-\frac{2c}{a}

= \bold{\frac{b^{2} -2ca}{a^{2}}}

#MarkAsBrainliest
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