Question

if
$\alpha \: and \: \beta \: are \: zeroes \: of \: f(x) = 5 {x}^{2} - 7x + 1 \: \: find \: 1 \div \alpha + 1 \div \beta$
​

Answer 1

1/a +1/b = a+b/ab

a + b= - (-7/5) = 7/5

ab = 1/5

a + b/ ab = 7/5 x5/1 =7