Math, asked by nladri2307, 1 year ago

if
 \alpha  \:  \beta    \gamma
are the three zeroes of the polynomial and
p(x) \:  \:  \:  =  \: x {}^{3}  -  \: 64x \:  - 14
then what is the value of

 { \alpha }^{3}  +  \: { \beta }^{3} \:  +  { \gamma }^{3}

Answers

Answered by Anonymous
2
Hey,

f(x) = x {}^{3} - 64x - 14 \\ \\ \alpha \beta \gamma = - ( - 14) = 14 \\ \\ now \\ \alpha { }^{3} + \beta {}^{3} + \gamma {}^{3 } = 3 \alpha \beta \gamma = 3 \times 14 = 42
Hope it helps you!!!

nladri2307: its 42
nladri2307: calc. mistake
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