Math, asked by kanakmishra10, 11 months ago

If
 \alpha
and
 \beta
are the zeroes of quadratic polynomial
ax^{2} + bx + c

Then evaluate
 \alpha  -  \beta


Anonymous: ___k off

Answers

Answered by Anonymous
2

good \: morning \:  \\  \\ ( \alpha  -  \beta ) =  \sqrt{( \alpha  +  \beta ) {}^{2}  - 4 \alpha  \beta }   \\  \\  \alpha  +  \beta  =  - b \div a \\  \\ and \\  \\  \alpha  \beta  = c \div a \\  \\ ( \alpha  -  \beta ) =  \ \sqrt{(b {}^{2}  \div a {}^{2}) - 4c \div a }  \\  \\  \alpha  -  \beta ) =  \sqrt{b {}^{2} - 4ac }  \div a


kanakmishra10: ok thanks but how alpha - beta is equal to root alpha +beta hole square - 4 alpha beta
Anonymous: Expand R.H.S you will get L.H.S
kanakmishra10: sorry but i dont understand
Anonymous: sqr ( Alfa + Beta )² - 4 Alfa × Beta is equal to sqrt Alfa² + Beta² + 2Alfa × Beta - 4 Alfa × Beta is equal to Alfa² + Beta² - 2Alfa × Beta i
Anonymous: is equla to sqrt( Alfa - Beta )² is equal to Alfa - Beta
kanakmishra10: thanks
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