Math, asked by gauravbhulania05, 3 months ago

If
 \alpha
and
 \beta
are zeroes of polynomial 3x² -8x -3, then find the value of (
 (\alpha  +  \beta) ^{2}  - 2 \alpha  \beta

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Answers

Answered by Anonymous
26

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{\large{\pmb{\sf{\underline{Correct \; Question...}}}}}

★ If α(alpha) and β(beta) are the zeroes of polynomial 3x²-8x-3, then find the value of (α+β)² - 2αβ.

{\large{\pmb{\sf{\underline{Given \; that...}}}}}

★ Polynomial = 3x²-8x-3

★ α and β are the zeroes of polynomial

{\large{\pmb{\sf{\underline{To \; find...}}}}}

★ The value of (α+β)² - 2αβ

{\large{\pmb{\sf{\underline{Solution...}}}}}

★ The value of (α+β)² - 2αβ = 46/9

{\large{\pmb{\sf{\underline{Knowledge \; Required...}}}}}

Some knowledge about Quadratic Equations -

★ Sum of zeros of any quadratic equation is given by ➝ α+β = -b/a

★ Product of zeros of any quadratic equation is given by ➝ αβ = c/a

★ A quadratic equation have 2 roots

★ ax² + bx + c = 0 is the general form of quadratic equation

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━

{\large{\pmb{\sf{\underline{Full \; Solution...}}}}}

~ As we already provided with a polynomial as 3x²-8x-3 and it is said that α and β are the zeroes of polynomial and we are asked to find the value of (α+β)² - 2αβ. So firstly we have to find out the value for α+β and αβ by using the given formulas:

★ ax² + bx + c = 0 is the general form of quadratic equation.

★ Sum of zeros of any quadratic equation is given by ➝ α+β = -b/a

★ Product of zeros of any quadratic equation is given by ➝ αβ = c/a

\: \: \: \: \: \: \: \: \sf Here \begin{cases} & \sf{b \: is \: \bf{8}} \\ & \sf{a \: is \: \bf{3}} \\ & \sf{c \: is \: \bf{3}} \end{cases}\\ \\

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀Means,

⠀⠀⠀⠀● α+β = -8/3

⠀⠀⠀⠀● αβ = 3/3 = 1

~ Now finding the value of (α+β)² - 2αβ by using the above finded values. We just have to put the values and have to solve. Let us solve this question!

{\sf{\leadsto (\alpha + \beta)^{2} - 2 \alpha \beta}}

{\sf{\leadsto (-8/3)^{2} - 2(1)}}

{\sf{\leadsto -8/3 \times -8/3 - 2 \times 1}}

{\sf{\leadsto -8/3 \times -8/3 \times 2}}

{\sf{\leadsto 64/9 - 2/1}}

{\sf{\leadsto 46/9}}

  • Henceforth, the value of (α+β)² - 2αβ is 46/9
Answered by ananyaanuj2006
1

Let me answer it...

See the above attachment for answer.

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