If
and
are zeroes of polynomial 3x² -8x -3, then find the value of (
Answers
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★ If α(alpha) and β(beta) are the zeroes of polynomial 3x²-8x-3, then find the value of (α+β)² - 2αβ.
★ Polynomial = 3x²-8x-3
★ α and β are the zeroes of polynomial
★ The value of (α+β)² - 2αβ
★ The value of (α+β)² - 2αβ = 46/9
Some knowledge about Quadratic Equations -
★ Sum of zeros of any quadratic equation is given by ➝ α+β = -b/a
★ Product of zeros of any quadratic equation is given by ➝ αβ = c/a
★ A quadratic equation have 2 roots
★ ax² + bx + c = 0 is the general form of quadratic equation
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~ As we already provided with a polynomial as 3x²-8x-3 and it is said that α and β are the zeroes of polynomial and we are asked to find the value of (α+β)² - 2αβ. So firstly we have to find out the value for α+β and αβ by using the given formulas:
★ ax² + bx + c = 0 is the general form of quadratic equation.
★ Sum of zeros of any quadratic equation is given by ➝ α+β = -b/a
★ Product of zeros of any quadratic equation is given by ➝ αβ = c/a
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀Means,
⠀⠀⠀⠀● α+β = -8/3
⠀⠀⠀⠀● αβ = 3/3 = 1
~ Now finding the value of (α+β)² - 2αβ by using the above finded values. We just have to put the values and have to solve. Let us solve this question!
- Henceforth, the value of (α+β)² - 2αβ is 46/9
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