Question

IF:-
$\bf{\frac{x^{2}-14x+49}{x^{2}-49}=\frac{3}{17}}$

Find the value of x.​

Answer 1

$\small\tt\purple{\underline{\boxed{Question}}}$

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IF:-

$\bf{\frac{x^{2}-14x+49}{x^{2}-49}=\frac{3}{17}}$

$\small\bf{Find\: the\: value\: of\ x.}$

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$\small\tt\purple{\underline{\boxed{Solution}}}$

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$\bf{\frac{x^{2}-14x+49}{x^{2}-49}=\frac{3}{17}}$

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$\bf{\frac{x^{2}-2\times 7\times x+49}{x^{2}-7^{2}}=\frac{3}{17}}$

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$\bf{\frac{(x-7)^{2}}{(x-7)(x+7)}=\frac{3}{17}}$

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$\bf{(x-7)\times 17}={3\times(x+7)}$

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$\bf{17x-119= 3x+21}$

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$\bf{17x-3x= 21+119}$

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$\bf{14x= 140}$

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$\bf{x}= \cancel \frac{140}{14}$

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$\bf{\boxed{x\:=\:10}}$

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$\small\tt\purple{\underline{\boxed{Thanks}}}$

Answer 2

Answer:

The value of the X = 10......

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