Question

if
$\cos(?) + \sin(?) = \sqrt{2} \cos(?)$
then prove
$\cos(?) - \sin(?) = \sqrt{2} \sin(?)$

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Answer 1

Answer:

Given,

cos x + sinx = √ 2 cos x , then (√2 -1 ) cos  x = sin x

on multiplying both sides by (√2+1) , we get

(√2+1)(√2-1) cos x  =  (√2+ 1) sin x

⇒ cos x = √2 sin x + sin x

⇒ cos x -sin x = √ 2 sin x

Good luck :)))

Step-by-step explanation: