Question

If $\dfrac{sin^4A}{sin^2B}+\dfrac{cos^4A}{cos^2B}=1$, then prove that :

$sin^4A+sin^4B=2sin^2Asin^2B$​

Answer 1

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TRIGONOMETRY

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KEY POINTS TO REMEMBER :-

☸️sin²A = (1 - cos²A)

☸️ cos²A = (1 - sin²A)

☸️ sin²A + cos²A = 1

☸️ cos²B + sin²B = 1

☸️ Normal linear equation solution

☸️ LHS and RHS concepts.

☸️ Basic Trigonometric ratios :-

Sin A = p/h

CosA = b/h

tanA = p/b

CosecA = h/p

SecA = h/b

CotA = b/p

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Answer 2

hope it is helpful tp you