Question

If $\dfrac{sinx}{a}=\dfrac{cosx}{b}=\dfrac{tanx}{c}=k$ ,

then $bc+\dfrac{1}{ck}+\dfrac{ak}{1+bk}=$

(a) $k\left(a+\dfrac{1}{a}\right)$

(b) $\dfrac{1}{k}\left(a+\dfrac{1}{a}\right)$

(c) $\dfrac{1}{k^2}$

(d) $\dfrac{a}{k}$​

Answer 1

refer the attachment

mark as brainliest

Answer 2

Answer:

option b is correct answer