Question

if
$\frac{1}{ \tan( \alpha ) } = \frac{1}{2 - \sqrt{3} }$
then
${cot}^{3} \alpha + {tan}^{3} \alpha \: \: equals \: to$
help please!!​

Answer 1

Step-by-step explanation:

cota = (2-√3)

tana = (2+√3)

a^3+b^3 =(a+b)(a^2-ab+b^2)

= (2+√3+2-√3)(8+6-(1))

=(4)(13)

= 52