Math, asked by beliver0660, 1 month ago

if
 \frac{2}{b}  =  \frac{1}{a}  +  \frac{1}{c}
then a,b,c are in​


Anonymous: hi brother

Answers

Answered by mathdude500
4

\underline\blue{\bold{Given \:  Question :-  }}

\bf \:if \: \dfrac{2}{b} = \dfrac{1}{a} + \dfrac{1}{c}

then a, b, c are in

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\begin{gathered}\Large{\bold{\pink{\underline{Basic \:  Concepts \::}}}}  \end{gathered}

  • An arithmetic progression (AP) is a sequence of numbers in which each succeeding number is obtained either by adding or subtracting a specific number called common difference. The general form of AP is: a, a + d, a + 2d, …

  • A geometric progression (GP) is a sequence of numbers in which each succeeding number is obtained multiplying a specific number called common ratio. The general form of GP is: a, ar, ar^2, ,….

  • A sequence of numbers is said to be a harmonic progression if the reciprocal of those numbers are in AP. In simple terms, a,b,c,d,e,f are in HP if 1/a, 1/b, 1/c, 1/d, 1/e, 1/f are in AP.

  • For two terms ‘a’ and ‘b’,
  • Harmonic Mean = (2 a b) / (a + b)
  • For two numbers, if A, G and H are respectively the arithmetic, geometric and harmonic means, then
  • A ≥ G ≥ H
  • A H = G^2, i.e., A, G, H are in GP

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\begin{gathered}\Large{\bold{\purple{\underline{CaLcUlAtIoN\::}}}} \\ \end{gathered}

\bf \:\dfrac{2}{b} = \dfrac{1}{a} + \dfrac{1}{c}

\bf\implies \:\dfrac{1}{b} + \dfrac{1}{b}  = \dfrac{1}{a} + \dfrac{1}{c}

\bf\implies \:\dfrac{1}{b}  - \dfrac{1}{a}  = \dfrac{1}{c}  - \dfrac{1}{b}

\bf\implies \:\dfrac{1}{a}, \dfrac{1}{b}, \dfrac{1}{c}  \: are \: in \: AP

\bf\implies \:a,b,c \: are \: in \: HP.

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mathdude500: answers are
mathdude500: Figure 1, 110
mathdude500: Fig 2 105
Anonymous: ok
mathdude500: not able to answer there
Anonymous: thanks
mathdude500: sorry please
mathdude500: 4 follow the question
Anonymous: no problem
mathdude500: okay
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