Question

If
$\frac{3a + 8b}{3c + 8d} = \frac{3a - 8b}{3c - 8d}$
then show that a,b,c,d are in proportion with proper steps
plz answer
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Answer 1

$\frac{3a + 8b}{3c + 8d} = \frac{3a - 8b}{3c - 8d}$

or

$\frac{3a + 8b}{3a - 8b} = \frac{3c + 8d}{3c - 8d}$

using corponeando and devideando

6a/8b = 6c/8d

a/b = c/d

so

a:b::c:d

hence a,b,c and are in proportion

Answer 2

Answer:

mujai dobara sa fallow kardo please answer mut karna Sif fallow kardena ok