Question

If
$\frac{5}{x} + 6y = 13$
and
$\frac{3}{x} + 4y = 7$
find value of
$y$

​

Answer 1

Step-by-step explanation:

$\frac{5}{x} + 6y = 13$

Multiply eqn by 3 ,we get

$\frac{15}{x} + 18y = 39$

Now second equation

$\frac{3}{x} + 4y = 7$

Multiply eqn by 5,we get

$\frac{15}{x} + 20y = 35$

Subtract above two formed equations

we will get

-2y = 4

y = -2

Hope it helps :-)