Question

If
$\frac{ a-3b}{b}, \frac{ 3a-3b}{b}, \frac{5a-3b}{b}, \frac {7a - 3b}{b}, ...$
is an A.P. with common difference 3, then $\frac{a}{b} =$

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Answer 1

Step-by-step explanation:

the given terms are in A.P and d = 3,

then (3a - 3b) / b - (a - 3b) / b = 3

=> (3a - 3b - a + 3b) / b = 3

=> (3a - a) / b = 3

=> 2a / b = 3

=> a / b = 3/2