Question

If
$\frac{a(b + c - a)}{ log(a) } = \frac{b(c + a - b)}{ log(b) } = \frac{c(a + b - c)}{ log(c) }$
Show that
${b}^{a} {a}^{b} = {c}^{a} {a}^{c} = {b}^{c} {c}^{b}$
​

Answer 1

Answer:

If

$\frac{a(b + c - a)}{ log(a) } = \frac{b(c + a - b)}{ log(b) } = \frac{c(a + b - c)}{ log(c) }$

Show that

${b}^{a} {a}^{b} = {c}^{a} {a}^{c} = {b}^{c} {c}^{b}$

Step-by-step explanation:

If

$\frac{a(b + c - a)}{ log(a) } = \frac{b(c + a - b)}{ log(b) } = \frac{c(a + b - c)}{ log(c) }$

Show that

${b}^{a} {a}^{b} = {c}^{a} {a}^{c} = {b}^{c} {c}^{b}$