Math, asked by tnwramit1, 1 year ago

If
 \frac{a}{b + c}  +  \frac{b}{c + a}  +  \frac{c}{a + b}  = 1
Then find
 \frac{ {a}^{2} }{b + c}  +  \frac{ {b}^{2} }{c + a}  +  \frac{ {c}^{2} }{a + b}  = ........
A) 0
B) 1
C)2
D)3

(EXAM CPO 2012)

Try it (time limit 1 minute only)
Comment for shortcut.

Answers

Answered by abhi178
10
a/(b + c) + b/(c + a) + c/(a + b) = 1
multiple both sides with (a + b+ c)

a(a + b + c)/(b+c) + b(a + b + c)/(c + a) + c(a + b + c)/(a + b) = (a + b + c)

a²/(b + c) + a(b+c)/(b+c) + b²/(c + a) + b(c + a)/(c + a) + c²/(a + b) + c(a+b)/(a + b)
= (a + b + c)

a²/(b + c) + b²/(c + a ) + c²/(a + b ) + (a + b+ c ) = (a + b + c )

a²/(b + c ) + b²/(c + a) + c²/(a + b) = 0

hence, option ( A ) is correct

tnwramit1: I have my own tricks
abhi178: thats good . but its my trick and concept
tnwramit1: u can use this
tnwramit1: just assume 1 variable as zero
tnwramit1: I assumed c as zero
tnwramit1: now again try to make other ad zero but it now we can't make b or a zero so we will put 1 in place of any 1 variable
tnwramit1: I put 1 in place of b
tnwramit1: we get a+1/a=1 then find a²+1/a
tnwramit1: so now to make a to a² multiple a with it
tnwramit1: the then u get ur ans as zero
Similar questions