Question

If
$\frac{x}{2} = \frac{1}{2x} + 1$
so what is the Value of
$( \frac{x {3}^{} }{} - \frac{1}{x {}^{3} } )$
​

Answer 1

Step-by-step explanation:

$\frac{x}{2} = \frac{1}{2x} + 1 \\ xx=1+2x \\ x^{2}=1+2x \\ x^{2}-2x+1=1+1 \\ \sqrt{\left(x-1\right)^{2}}=\sqrt{2} \\ \\ \\ x=\sqrt{2}+1 \\ x=1-\sqrt{2}$