Question

If $(\frac{x}{y})^{n-1} =(\frac{y}{x})^{n-3}$ then n is =

Answer 1

$(\frac{x}{y})^{n-1} =(\frac{y}{x})^{n-3} \\ ( { \frac{y}{x} })^{1 - n} = (\frac{y}{x})^{n-3} \\ 1 - n = n - 3 \\ 2n = 4 \\ n = 2$

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