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Answered by
6
Answer:
1 / 2
Step-by-step explanation:
Given----> Cos²α - Sin²α = 1 / 2
To find ------> Value of ( Cos⁴α - Sin⁴α )
Solution------> ATQ,
Cos²α - Sin²α = 1 / 2
Now , Cos⁴α - Sin⁴α
=> ( Cos²α )² - ( Sin²α )²
We know that,
( a² - b² ) = ( a + b ) ( a - b ) , applying it we get,
=> ( Cos²α + Sin²α ) ( Cos²α - Sin²α )
We know that , Cos²α + Sin²α = 1 , we get,
=> ( 1 ) ( Cos²α - Sin²α )
Putting ( Cos²α - Sin²α ) = 1 / 2 , we get,
=> ( 1 ) ( 1 / 2 )
=> 1 / 2
Answered by
1
Answer:
1/2 is your answer dear hope it's helpful dear genius good morning
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