Question

If
$log_{10}(3) = 0.477$
,then find the number of digits in
${3}^{40}$
​

Answer 1

Answer

20

Step-by-step explanation:

take log3^40

= 40log3

put value of log 3

and solve

40X0.477

=19.08

aproxx

20

Answer 2

Answer:

19

Step-by-step explanation:

y=3^40

logy=log3^40

=40*log3

logy=40*0.477

y=10^19.09

=10^19*10^0.09

=10^9/100*10^19

=1.23*10^19

So number of digits=19