Question

if
$log_{3}( {x}^{2} - 5x + 7) < 0$
then the interval in which 'x' lies is

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Answer 1

Step-by-step explanation:

We have,

$log_{3}( {x}^{2} - 5x + 7 ) < 0$

$\implies {x}^{2} - 5x + 7 < 1$

$\implies {x}^{2} - 5x + 6 < 0$

$\implies(x - 3)(x - 2) < 0$

$\implies \: x \in(2 \: \: to \: \: 3)$

Answer 2

Answer:

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