Question

if
$p(x) is \: 2 + x + 2 {x}^{2} - {x}^{3}$
then find p(0) & p(1)

​

Answer 1

Step-by-step explanation:

$p(x) = 2 + x + 2 {x}^{2} - {x}^{3} \\ \\ p(0) = 2 + 0 + 2 \times 0 - 0 \\ \\ = 2 + 0 \\ \\ = 2 \\ \\ p(1) = 2 + 1 + 2 \times {1}^{2} - {1}^{3} \\ \\ = 2 + 1 + 2 - 1 \\ \\ = 5 - 1 \\ \\ = 4$