Question

If
$( {px}^3 + {3) }^{2} = {p}^{2} {x}^{6} + {3x}^{3} + 9 {?}$
find p
​

Answer 1

Answer:

see ans in the form of image.

Answer 2

$\huge{\mathfrak{\red{Solution}}}$

$( {px}^{3} + {3)}^{2} = {p}^{2} {x}^{6 }+ {3x}^{3} + 9 \\ {p}^{2} {x}^{6} + 9 + 6p {x}^{3} = p {}^{2} x {}^{6} + {3x}^{3} + 9 \\ 6p {x}^{3} = {3x}^{ 3} \\ 6p = 3 \\ p = \frac{1}{2}$

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