Question

If
$sec = \frac{15}{13}$
then find sin and cos
​

Answer 1

Step-by-step explanation:

$\sec = \frac{15}{13} \\ \sec = \frac{1}{cos} \\ \sec = \frac{h}{b}$

h=15

b=13

By pythagoras theorem

${15}^{2} = {13}^{2} + {x}^{2} \\ 225 = 169 + {x}^{2} \\ 225 - 169 = {x}^{2} \\ 56 = {x}^{2} \\ x = \sqrt{56} = 2 \sqrt{14}$

$\sin = \frac{p}{b} = \frac{2 \sqrt{14} }{15}$

$\cos = \frac{b}{h} = \frac{13}{15}$