Math, asked by sohamnimbalkar457, 11 months ago

If
sec =  \frac{15}{13}
then find sin and cos

Answers

Answered by Bhavyagoyal18
1

Step-by-step explanation:

 \sec =  \frac{15}{13}  \\  \sec =  \frac{1}{cos}  \\  \sec =  \frac{h}{b}

h=15

b=13

By pythagoras theorem

 {15}^{2}  =  {13}^{2}  +  {x}^{2}  \\ 225 = 169 +  {x}^{2}  \\ 225 - 169 =  {x}^{2} \\ 56 =  {x}^{2}  \\ x =  \sqrt{56}  = 2 \sqrt{14}

 \sin =  \frac{p}{b}  =  \frac{2 \sqrt{14} }{15}

 \cos =  \frac{b}{h}  =  \frac{13}{15}

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