If , what is the value of cotθ + cosecθ?
Answers
Answer:
The value of cot θ + cosecθ is 2.
Step-by-step explanation:
Given : sin θ = ⅘ …….(1)
By using an identity , sin² θ + cos² θ = 1
(⅘)² + cos² θ = 1
16/25 + cos² θ = 1
cos² θ = 1 - 16/25
cos² θ = (25 - 16)/25
cos² θ = 9/25
cosθ = √9/25
cosθ = ⅗ …….(2)
cot θ + cosecθ (Given)
cosθ/sin θ + 1/sinθ
[By using the identity, cotθ = cosθ/sinθ & cosecθ = 1/sinθ]
= (⅗)/(4/5) + 1/(⅘)
[From eq 1 & 2]
= ⅗ × 5/4 + 1 × 5/4
= ¾ + 5/4
= (3 + 5)/4
= 8/4
cot θ + cosecθ = 2
Hence, the value of cot θ + cosecθ is 2.
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Solution :
Given, sinθ = 4/5
= perpendicular / hypotenuse
∴ perpendicular = 4 units
& hypotenuse = 5 units
∴ base = √(5² - 4²) units
= 3 units
Then, cotθ = base / perpendicular
= 3/4
and cosecθ = 1/sinθ
= 1/(4/5)
= 5/4
∴ cotθ + cosecθ
= 3/4 + 5/4
= (3 + 5)/4
= 8/4
= 2 (Ans.)