Math, asked by SubhodeepChapadar, 11 months ago

If
 \sqrt[3]{ \frac{x}{729} }  +  \sqrt[3]{ \frac{8x}{729} }  +  \sqrt[3]{ \frac{27x}{5832} }  = 1
then find the value of x

Answers

Answered by Hemu1432
2

Answer:

welcome to my answer

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cube root of 0.008 = 0.2

cube root of 0.027 = 0.3

cube root of 729 = 9

cube root of 512 = 8

0.2/0.3 x 8/9 x 27/16

=1

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