Question

If
$\sqrt[3]{ \frac{x}{729} } + \sqrt[3]{ \frac{8x}{729} } + \sqrt[3]{ \frac{27x}{5832} } = 1$
then find the value of x
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Answer 1

Answer:

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cube root of 0.008 = 0.2

cube root of 0.027 = 0.3

cube root of 729 = 9

cube root of 512 = 8

0.2/0.3 x 8/9 x 27/16

=1

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